Slip 10 - B) Create a C++ class City with data members City_code, City_name, population. Write necessary member functions for the following: i, Accept details of n cities ii. Display details of n cities in ascending order of population. iii. Display details of a particular city. (Use Array of object and to display city information use manipulators.)

 Solution:

#include<iostream.h>

#include<conio.h>

#include<iomanip.h>

#include<stdlib.h>

#include<string.h>

 void searchcity();

 char n[10],c[10];

 class city

 {

public:

int population,city_code;

char name[40],e[10];

 void accept()

{

 cout<<"\n Enter name of city:";

cin>>name;

 cout<<"\n Enter name of city_code:";

cin>>city_code;

 cout<<"\n Enter the population of city:";

cin>>population;

}

void sort(city &r1,city &r2)

{

city rt;

if(r1.population>r2.population)

{

 rt=r1;

 r1=r2;

 r2=rt;

}

}

 void display()

{

cout<<"\n Name of City :"<<setw(15)<<name<<endl;

cout<<"\n Population :"<<setw(15)<<population<<endl;

cout<<"\n City Code:"<<setw(15)<<city_code<<endl;

}

 void searchcity()

{

if(strcmp(name,c)==0)

{

cout<<"\n name: "<<name<<"\n Population.: "<<population;

}

}

};

void main()

{

clrscr();

city t[30];

int num,ch,population;

char cont;

cout<<"\n 1.Accept & display ";

cout<<"\n 2.Ascending";

cout<<"\n 3.Search by city";

do

 {

cout<<"\n Enter your choice: ";

cin>>ch;

switch(ch)

{

case 1: cout<<"\n How many records you want to enter: ";

cin>>num;

for(int i=0;i<num;i++)

{

t[i].accept();

}

 for(i=0;i<num;i++)

{

t[i].display();

}

 break;

 case 2:

 for(i=0;i<num;i++)

{

for(int j=i+1;j<num;j++)

t[i].sort(t[i],t[j]);

t[i].display();

}

 break;

 case 3: cout<<"\n Enter city name: ";

cin>>c;                                  

for(i=0;i<num;i++)

{

t[i].searchcity();

}

break;

}

 cout<<"\n Do you want to continue: ";

cin>>cont;

}

 while(cont=='Y'||cont=='y');

getch();

}