Slip 10 - B) Write a program, which accepts a number n and displays each digit in words. Example: 6702 Output = Six-Seven-Zero-Two

Solution:

#include<stdio.h>

int main()

{

 int a,n=1,x,m=0,p;

 printf("enter no :");

 scanf("%d",&a);

 p=a;

 while(p!=0)

 {

  p=p/10;

  n=n*10;

    }

 while(a!=0)

 {

     n=n/10;

  x=a%10;

  a=a/10;

  m=m+(x*n);

 }

  while(m!=0)

 {

  x=m%10;

  m=m/10;

    switch(x)

   {

case 0:

      printf("Zero");

      break;

case 1:

      printf("one - ");

      break;

case 2:

      printf("Two - ");

      break;

case 3:

      printf("Three - ");

      break;

case 4:

      printf("Four - ");

      break;

case 5:

      printf("Five - ");

      break;

case 6:

      printf("Six - ");

      break;

case 7:

      printf("Seven - ");

      break;

case 8:

      printf("Eight - ");

      break;

case 9:

      printf("Nine -");

      break;

     }

 }

}