Solution:
#include<stdio.h>
int printIntersection(int arr1[], int arr2[], int m, int n)
{
int i = 0, j = 0;
while (i < m && j < n)
{
if (arr1[i] < arr2[j])
i++;
else if (arr2[j] < arr1[i])
j++;
else /* if arr1[i] == arr2[j] */
{
printf(" %d ", arr2[j++]);
i++;
}
}
}
int main()
{
int arr1[] = {1, 2, 4, 5, 6};
int arr2[] = {2, 3, 5, 7};
int m = sizeof(arr1)/sizeof(arr1[0]);
int n = sizeof(arr2)/sizeof(arr2[0]);
printIntersection(arr1, arr2, m, n);
getchar();
return 0;
}
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