Slip 25 - B) Write a menu driven program for the following option 1. Check input number is Armstrong or not 2. Check input number is Perfect or not

Solution:

#include <stdio.h>

void main()

{

    int fig_code;

    int number, originalNumber, remainder, result = 0;

    int n,i=1,sum=0;

while(1)

     {

    printf("-------------------------\n");

    printf(" 1 --> Armstrong or not\n");

    printf(" 2 --> Perfect or not \n");

    printf("-------------------------\n");

    printf("Enter the Figure code\n");

    scanf("%d", &fig_code);

    switch(fig_code)

    {

 

    case 1:

        printf("Enter a three digit integer: ");

       scanf("%d", &number);

       originalNumber = number;

    while (originalNumber != 0)

    {

        remainder = originalNumber%10;

        result += remainder*remainder*remainder;

        originalNumber /= 10;

    }

    if(result == number)

        printf("%d is an Armstrong number.",number);

    else

        printf("%d is not an Armstrong number.",number);

        break;

    case 2:

    printf("Enter a number: ");

    scanf("%d",&n);

    while(i<n){

      if(n%i==0)

           sum=sum+i;

         i++;

    }

    if(sum==n)

      printf("%d is a perfect number",i);

    else

      printf("%d is not a perfect number",i);

     

                break;

    default:

        exit(0);    }

}}