Slip 27 - A) Write a java program to accept a number from user, If it is greater than 1000 then throw user defined exception “Number is out of Range” otherwise display the factors of that number. (Use static keyword).

Solution :

import java.io.*;

class NumOutRange extends Exception{}

class Slip27A{

static int n;

public static void main( String args[]){

DataInputStream dr = new DataInputStream(System.in);

try {

System.out.print("Enter Number : ");

n = Integer.parseInt(dr.readLine());

if(n>1000){

throw new NumOutRange();

}else{

for(int i=1; i<n; i++){

if(n%i==0){

System.out.println(i + " ");

    }

   }

  }

} catch (NumOutRange nz) {

System.out.println("Num is out of range..!");

}

catch (Exception e){

System.out.println(""+e.getMessage());

  }

 }

}

Output: