Slip 4 - A) Define a class Employee having private members — id, name, department, salary. Define parameterized constructors. Create a subclass called “Manager” with private member bonus. Create 3 objects of the Manager class and display the details of the manager having the maximum total salary (salary + bonus).

 Solution:

<?php

class Employee

{

private $eid,$ename,$edept,$sal;

function __construct($a,$b,$c,$d)

{

$this->eid=$a;

$this->ename=$b;

$this->edept=$c;

$this->sal=$d;

}

public function getdata()

{

return $this->sal;

}

public function display()

{

echo $this->eid."

";

echo $this->ename."

";

echo $this->edept."

";

}

}

class Manager extends Employee

{

private $bonus;

public static $total1=0;

function __construct($a,$b,$c,$d,$e)

{

parent::__construct($a,$b,$c,$d);

$this->bonus=$e;

}

public function max($ob)

{

$sal=$this->getdata();

$total=$sal+$this->bonus;

if($total>self::$total1)

{

self::$total1=$total;

return $this;

}

else

{

return $ob;

}

}

public function display()

{

parent::display();

echo self::$total1;

}

}

$ob=new Manager(0,"ABC","",0,0);

$ob1=new Manager(1,"ramdas","computer",28000,2000);

$ob=$ob1->max($ob);

$ob2=new Manager(2,"ramdas1","computer",30000,2500);

$ob=$ob2->max($ob);

$ob3=new Manager(3,"ramdas2","computer",32000,3000);

$ob=$ob3->max($ob);

$ob4=new Manager(4,"ramdas","computer",28000,4000);

$ob=$ob4->max($ob);

$ob5=new Manager(5,"ramdas","computer",28000,5000);

$ob=$ob5->max($ob);

$ob->display();

?>