Solution:
slip6-p1-q2.html
<html>
<head>
<script>
function showUser(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("txtHint").innerHTML = this.responseText;
}
};
xmlhttp.open("GET","slip6-p2-q2.php?q="+str,true);
xmlhttp.send();
}
}
</script>
</head>
<body>
<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="harsh">harsh</option>
<option value="lokya">lokya</option>
<option value="Aryan">Aryan</option>
<option value="Yash">Yash</option>
</select>
</form>
<br>
<div id="txtHint"><b>Person info will be listed here...</b></div>
</body>
</html>
slip6-p2-q2.php
<?php
$host = "localhost";
$user = "root";
$password = "";
$dbname = "q3";
$con = mysqli_connect($host, $user, $password,$dbname);
if (!$con) {
die("Connection failed: " . mysqli_connect_error());
}
?>
<html>
<head>
<style>
table {
width: 100%;
border-collapse: collapse;
}
table, td, th {
border: 1px solid black;
padding: 5px;
}
th {text-align: left;}
</style>
</head>
<body>
<?php
$q = $_GET['q'];
mysqli_select_db($con,"ajax");
$sql="SELECT * FROM emp WHERE name = '".$q."'";
$result = mysqli_query($con,$sql);
echo "<table>
<tr>
<th>Eid</th>
<th>Employeename</th>
<th>Designation</th>
<th>Contact Number</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['designation'] . "</td>";
echo "<td>" . $row['number'] . "</td>";
//echo "<td>" . $row['Job'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
</body>
</html>
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