Slip 8 - B) Create a C++ class Person with data members Person_name, Mobile_number, Age, City. Write necessary member functions for the following: i. Search the mobile number of given person. ii. Search the person name of given mobile number. iii. Search all person details of given city. (Use function overloading)

 Solution:

#include<iostream>

#include<conio.h>

#include<string.h>

using namespace std;

class person

{

public:

   int no,mob; 

   char name[10],city[10];

   void acc() // function overloading 

   {

    cout<<"\nEnter person no : ";

      cin>>no;

      cout<<"\nEnter person name : ";

      cin>>name;

      cout<<"\nEnter person city : ";

      cin>>city;

      cout<<"\nEnter person mob no : ";

      cin>>mob;

   }

   void acc(char nme[]) // function overloading 

   {

    if(strcmp(nme,name)==0)

      {

      cout<<"\nPerson name   : "<<name;

      cout<<"\nPerson mob no : "<<mob<<endl;

      }

   }

   void acc(int mno)  // function overloading 

   {

    if(mno==mob)

      {

      cout<<"\nPerson name   : "<<name;

      cout<<"\nPerson mob no : "<<mob<<endl;

      }

   }

   void dis()

   {

      cout<<"\nPerson details"<<endl;

      cout<<"\nPerson no     : "<<no;

      cout<<"\nPerson name   : "<<name;

      cout<<"\nPerson city   : "<<city;

      cout<<"\nPerson mob no : "<<mob<<endl;

   }

};

int main()

{

   char nme[10];

   int mno,i,no,ch;// mno=mobile no , no=total person no , ch=choice

   person p[20];

   do{

   cout<<"\n1.Accept person details\n2.Display person details\n3.To search the mobile number of a given person\n4.To search the Person details of a given mobile number\n5.Exit\nEnter your choice :- ";

   cin>>ch;

   switch(ch)

   {

   case 1:cout<<"Enter how many Person Details you want to enter: ";

    cin>>no;

          

          for(i=0;i<no;i++)

    {

p[i].acc();

    }

         break;

   case 2:for(i=0;i<no;i++)

    p[i].dis();

          break;

   case 3:cout<<"\nEnter person name search for mob no : ";

    cin>>nme;

          for(i=0;i<no;i++)

  p[i].acc(nme);

          break;

   case 4:cout<<"\nEnter mob no search for person name : ";

  cin>>mno;

  for(i=0;i<no;i++)

  p[i].acc(mno);

          break;

   }

   }while(ch!=5);

   return 0;

}